Integrand size = 16, antiderivative size = 42 \[ \int \frac {1}{\sqrt {3-6 x^2-2 x^4}} \, dx=\sqrt {\frac {1}{6} \left (-3+\sqrt {15}\right )} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {1}{3} \left (3+\sqrt {15}\right )} x\right ),-4+\sqrt {15}\right ) \]
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Time = 0.06 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {1109, 430} \[ \int \frac {1}{\sqrt {3-6 x^2-2 x^4}} \, dx=\sqrt {\frac {1}{6} \left (\sqrt {15}-3\right )} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {1}{3} \left (3+\sqrt {15}\right )} x\right ),-4+\sqrt {15}\right ) \]
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Rule 430
Rule 1109
Rubi steps \begin{align*} \text {integral}& = \left (2 \sqrt {2}\right ) \int \frac {1}{\sqrt {-6+2 \sqrt {15}-4 x^2} \sqrt {6+2 \sqrt {15}+4 x^2}} \, dx \\ & = \sqrt {\frac {1}{6} \left (-3+\sqrt {15}\right )} F\left (\sin ^{-1}\left (\sqrt {\frac {1}{3} \left (3+\sqrt {15}\right )} x\right )|-4+\sqrt {15}\right ) \\ \end{align*}
Result contains complex when optimal does not.
Time = 10.04 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.07 \[ \int \frac {1}{\sqrt {3-6 x^2-2 x^4}} \, dx=-\frac {i \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {-1+\sqrt {\frac {5}{3}}} x\right ),-4-\sqrt {15}\right )}{\sqrt {-3+\sqrt {15}}} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 83 vs. \(2 (37 ) = 74\).
Time = 0.60 (sec) , antiderivative size = 84, normalized size of antiderivative = 2.00
method | result | size |
default | \(\frac {3 \sqrt {1-\left (1+\frac {\sqrt {15}}{3}\right ) x^{2}}\, \sqrt {1-\left (1-\frac {\sqrt {15}}{3}\right ) x^{2}}\, F\left (\frac {x \sqrt {9+3 \sqrt {15}}}{3}, \frac {i \sqrt {10}}{2}-\frac {i \sqrt {6}}{2}\right )}{\sqrt {9+3 \sqrt {15}}\, \sqrt {-2 x^{4}-6 x^{2}+3}}\) | \(84\) |
elliptic | \(\frac {3 \sqrt {1-\left (1+\frac {\sqrt {15}}{3}\right ) x^{2}}\, \sqrt {1-\left (1-\frac {\sqrt {15}}{3}\right ) x^{2}}\, F\left (\frac {x \sqrt {9+3 \sqrt {15}}}{3}, \frac {i \sqrt {10}}{2}-\frac {i \sqrt {6}}{2}\right )}{\sqrt {9+3 \sqrt {15}}\, \sqrt {-2 x^{4}-6 x^{2}+3}}\) | \(84\) |
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none
Time = 0.08 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.19 \[ \int \frac {1}{\sqrt {3-6 x^2-2 x^4}} \, dx=\frac {1}{6} \, \sqrt {\sqrt {5} \sqrt {3} + 3} {\left (\sqrt {5} \sqrt {3} - 3\right )} F(\arcsin \left (\frac {1}{3} \, \sqrt {3} \sqrt {\sqrt {5} \sqrt {3} + 3} x\right )\,|\,\sqrt {5} \sqrt {3} - 4) \]
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\[ \int \frac {1}{\sqrt {3-6 x^2-2 x^4}} \, dx=\int \frac {1}{\sqrt {- 2 x^{4} - 6 x^{2} + 3}}\, dx \]
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\[ \int \frac {1}{\sqrt {3-6 x^2-2 x^4}} \, dx=\int { \frac {1}{\sqrt {-2 \, x^{4} - 6 \, x^{2} + 3}} \,d x } \]
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\[ \int \frac {1}{\sqrt {3-6 x^2-2 x^4}} \, dx=\int { \frac {1}{\sqrt {-2 \, x^{4} - 6 \, x^{2} + 3}} \,d x } \]
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Timed out. \[ \int \frac {1}{\sqrt {3-6 x^2-2 x^4}} \, dx=\int \frac {1}{\sqrt {-2\,x^4-6\,x^2+3}} \,d x \]
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